Can somebody work this simple problem for me for ten points?

It's not homework and I don't have time to relearn the math. I just need the answer.





i need to know the length in inches of a rectangle that is 1/8'; wide if it's area is equal to that of a circle that is 1 1/2'; in diameterCan somebody work this simple problem for me for ten points?
we are given diameter so radius R = 1.5/2 = 0.75


circle area equation is A = piR^2, so A = 3.1415 x (0.75)^2 = 1.77 square inches. So now we mash that area into a rectangle with one side being 1/8, or 0.125 inches, we have an equation 1.77 = 0.125 x L, or L = 1.77/0.125 = 14.14Can somebody work this simple problem for me for ten points?
Sure, since the circle has a diameter of 1.5 inches, we know that its radius is .75 inches (since the radius of a circle is half the length of the circle's diameter). So if the circle has a radius of .75 inches, then that circle's area is .5625 * pi (since the area of a circle is pi * r^2).





Now the formula for the area of a rectangle is l * w. So if a rectangle has that same area (.5625 * pi) and it also has a width of .125 (1/8) inches, then we look at an equation:





.5625 * pi = .125 * length





so





length = (.5625 * pi) / .125





finally





length = 14.13716694115407 inches