I need to know how to work this out. I have the answer just need to know how to get it.?

How many kg of carbon dioxide are produced when 150 kg of glucose (C6H12O6) are fermented? C6H12O6-%26gt;2C2H5OH + 2CO2.I need to know how to work this out. I have the answer just need to know how to get it.?
C6H12O6 --%26gt; 2C2H5OH + 2CO2


1 mole of glucose will produce 2 moles of CO2


1 mole of glucose has a mass of 180.2 g


1 mole of CO2 has a mass of 44.01 g


150,000 g glucose / 180.2 g per mole = 832.4 moles


2x832.4 = 1664.8 moles of CO2


1664.8 moles x 44.01 g per mole = 73.3 kg CO2I need to know how to work this out. I have the answer just need to know how to get it.?
use the 'molar concept'.





So you've got your balanced reaction and it tells you that 1 molecule of glucose gives you 2 molecules of CO2.





Now find the molecular weight of glucose (180 g) and the molecular weight of carbon dioxide (44 g).





So 180g of glucose gives you 44 g of carbon dioxide.


i.e. 1 g of glucose gives you 44/180 g of co2


150 kg of glucose gives you (answer) g of CO2
Take the ratio of the molecular weights of the products.


(The CO2 to the alcohol) and multiply by 150Kg.