I need to know how to work this algebra graphing problem. I need to write an equation for the line with the?

Slope of 3 and the Y-intercept = -4 Thank you for your help.I need to know how to work this algebra graphing problem. I need to write an equation for the line with the?
The slope equation form y=mx+b is derived from the definition of the slope, m, and the y-intercept point (0,b):





Given slope m= (change in y)/(change in x) = (y2-y1)/(x2-x1)





let y-intercept (0,b) = (x1,y1)





Substituting: m = (y2-b)/(x2-0) = (y2-b)/x2





Rename point (x2,y2) = (x,y)





Now you have m= (y-b)/x





Solving for y: mx=y-b





or y=mx+b





Your problem gives m=3 and y-intercept = (0,-4) = (0,b)





therefore the answer is y=3x-4 doneI need to know how to work this algebra graphing problem. I need to write an equation for the line with the?
If you are being asked to write the equation of a line, then you have seen the slope-intercept form of a line:





y = mx + b





Do you know what each of those mean ?





If not, look in your book and pay attention in class.





y = 3x - 4





is the equation you want.





Now can you tell what m stands for ? what b stands for ?





QED
You are given slope, m = 3 and y-intercept, b = 4


Sub these values in the equation y = mx +b, you get


y = 3x + 4 (Answer)
y = mx + b


y = 3x - 4
y=3x-4